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Episode 2 of the series calculus; derivation of formula for finding derivative from first principles

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This is the second episode of the series calculus where the formula for finding derivative from first principles is derived or proved.<br />

In the episode a clever approach is used in deriving the formula for finding derivative from first principles.It will be so fun and helpful as the formula derived will be useful in future calculations.<br />

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[…] 7.Episode 2 of the series calculus; derivation of formula for finding derivative from first principles […]

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[…] sums 5.London dispersion forces 6.Adaptation of respiratory surfaces to function efficiently 7.Episode 2 of the series calculus; derivation of formula for finding derivative from first principles     […]

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[…] 144 Views Density in Chemistry Caleb Cheruiyot December 24, 2020 7:31 am 2 144 ViewsHow to derive density formula from ideal gas law Step 1; Identify the ideal gas law The Ideal gas law is PV = nRT Then making n/v the subject of the formula; n/v = P/RT Step 2:Multiply through by molar mass; m x P/RT = n/v x m 144 ViewsHow to derive density formula from ideal gas law Step 1; Identify the ideal gas law The Ideal gas law is PV = nRT Then making n/v the subject of the formula; n/v = P/RT Step 2:Multiply through by molar mass; m x P/RT = n/v x m Finally we get our density; =g/L = density = Pm/RT Where; P = pressure m = molar mass R = 0.0821 = constant T = Temperature Example; Oxygen gas was found to have density of 0.0067g/L at 20.0 0C and pressure of 800 torr.What is the molar mass? Using our formula; Density = Pm/RT Where P = Pressure m = molar mass R = 0.0821 T = Temperature Then from the question,we identify what we have in the right units; Density = 0.0067g/L m = molar mass in g/mol R = 0.0821 L/atm/mol/K P = Pressure = 800 torr Then converting everything to the required units; Density = 0.0067g/L P = 800 torr × 1atm/760 torr = 1.0526atm m = ? R = 0.0821 L/atm/mol/K T = 273 + 20.0 = 293K Then finishing on calculations; 0.0067g/L = 800/760 atm × m/0.0821 L/atm/mol/K × 293K 0.0067g/L = 800 m/62.396L/mol Therefore; m = 0.0067g/L × 62.396L/mol/800 Simplifying we get; m = 0.0005g/mol Reference; The featured image is attributed to the site http://www.desposiphotos.com     Recent articles 1.Dalton’s law of partial pressures 2.Education in ancient Egypt 3.Bachelor of education science degree 4.Integration by Riemann sums 5.London dispersion forces 6.Adaptation of respiratory surfaces to function efficiently 7.Episode 2 of the series calculus; derivation of formula for finding derivative from first principles […]


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